3x-4+2(3x)+17=-2-3x+(4^2-7)

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Solution for 3x-4+2(3x)+17=-2-3x+(4^2-7) equation: 



3x-4+2(3x)+17=-2-3x+(4^2-7)

We move all terms to the left:

3x-4+2(3x)+17-(-2-3x+(4^2-7))=0

We add all the numbers together, and all the variables

26x-(-2-3x+(4^2-7))+13=0



We calculate terms in parentheses: -(-2-3x+(4^2-7)), so:

-2-3x+(4^2-7)

determiningTheFunctionDomain
-3x-2+(4^2-7)

We add all the numbers together, and all the variables

-3x+7

Back to the equation:

-(-3x+7)



We get rid of parentheses

26x+3x-7+13=0

We add all the numbers together, and all the variables

29x+6=0

We move all terms containing x to the left, all other terms to the right

29x=-6

x=-6/29

x=-6/29

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